4 the maths lovers...??? help!!!

ohh...coool, thanks for the info and the link too.

 

Dudes I can prove that equation wrong. See this:
n^2 - n -41 = never divisible by 7
To prove it wrong, we have to prove that for a certain value of n, the answer must b divisible by 7. So we work counter-clock wise, we put the equation equal to anything divisible by 7. Now watch:
n^2 - n - 41 = 7
=> n^2 - n = 7+41
=> n(n-1) = 48
Now either n=48, or (n-1)=48. So we put n=48 in the above equation

48^2=2304

48^2 - 48 - 41=7
2215=7 (I know it doesn't sound right, but for the time being.....)

When we divide 2215 by 7, it gives 316.428. Not a whole nmber. Now try the other equation. i.e., n-1=48 => n=47

Putting in equation:

47^2=2209

47^2 - 47 -41=7
2209 - 47 - 41=7
2121=7

This solves to give the answer 303. A perfect whole number. I know nobody asked for a proof, Just for the fun...... Peace

 

hi buddy in the above u assumed one basic thing

" n^2 - n - 41 = 7 "


underlining assumption ::
(n2-n-41 )/7 =1

which is not the case
at most we can do is
(n2-n-41)/7 = x ...x being a postive or negative whole number

things we can arrive after assuming n2-n-41 divisible by 7
are for example
(n2-n-41 -7)(n2-n-41+7)(x) =0 ....


where x is any postive or negative integer.....

 

ahem,
n(n-1)=48..and u say n= 48
if n= 48 then n(n-1) =48*47 and not 48...caught u there

the answer is between 8 and 7 cuz for 8 n(n-1) =56 and for 7 its 42

 

Yea ur absolutely right dude. But i took some alien method of my own invention to get to the point. Put n = 47, and u have an answer divisible by 7. Thats the game!

 

:cry1:
JEE mein sabse weak was Math; Mathematical Induction especially.

And seeing you fellows ramble here
:cry2:

 

Dudes, I know my method is WEEEEEEEEE controversial, but i gave u the right answer. Didnt I? Now leave my thing alone... It wont make sense to many in the world, but it makes good sense to me. U got the answer, thats all what matters.

n2 - n - 41 = 7x where x=any real number. For any value of x, the relative value of n is right answer. Suit urselves. Its the closest i can get to common-to-the-world maths. Bye

 

n2-n-41 = x

assuming x is divisible by 7
therefore
(x-7)(x+7)(y)=0
when y is any number greater not equal to 0
therefore x2-49 =0

(n2 -n-41)2-49=0
or

(n2-n-41-7)(n2-n-41+7)=0


i.e. either
n2-n-48 =0

n2-n-34=0

none of them is factoriable ...there is one theorem to prove that...(something ac>b2)types dont exactly recall that...
so in turn n will come out to be an imaginary number.....

now the value of n2-n-41 will in turn be an imaginary number....
so the first assumption that x or n2-n-41 is divisible by 7 is wrong....

...this is not the complete ...but should be on the lines of solution....

 

Ahem ahem !!

I was the topper in Maths in school... even in graduation!!
and fortunately unfortunately i specialised in Maths teaching !!

I beg to differ with that abbreviation !!

 

Excuse me !!
1 - 1 - 41 = -43 ???
since when ??

 

Got to wait another year to know what that is hbbt:

 

I m losing my patience now !!

Evo guy did it right ... perfectly logical way of going about in such questions !!

 

seems an exception jus like the great "Shakuntala Devi"
coz in my school days grlz usually top subjs like "histry/geography/english/hindi"

newer ever maths....

 

** Clap !!

:nw:

Perfect !!

10 on 10

 

when i tell people that i scored meagre 32 in class VII and rose to 99 in Class X and continued the same till graduation....people dont believe...

I dont say i m brainy... but I had an excellent teacher (Tutor)
He made me fall in love with Maths....(figure of speech plzzz !!)
It all depends on who teaches you and how you are being taught .... simple !!

Was pathetic at Hindi.... never took hindi for class X
Was bad at history geography and stuff... scored the least in Social studies in Class X... it ruined my percentage

 

wtf? You being a math wiz and saying that n(n-1) = 48 would mean that either of the two is equal to 48 indicates that you are lying or just take jokes a tad too far.

 

now where did you get this from ?? (x-7)(x+7)(y) = 0??

i m trying to understand your solution...

 

well bjr... in proofs thats how you u go about it...

u assume either of the two to be equal to 48,... if you are able to prove the equation for any one ...then the solution holds good for that particular value...

I know it well what i m supporting !!

 

Now I'm unsure about my own memory since you seem to be so sure....oh well.

 

if a number is divisible by x it is also divisible by its -negative coz the quotient will be - of the other quotient ,,,

and y is any real number ....that compensates for other factors....